
Expert Answer
According to the rule of complement, we have: \[ P\ (\vec{E})\ =\ 1\ -\ P(E)\] For this we will use the formula of Combination as the order of the members does not matter in the set of cards containing $52 $ cards and $5$ cards were selected from the total of $52$ cards: \[C\left(n,r\right)=\frac{n!}{r!\left(n-r\right)!}\] Here $n= 52 $ and $r = 5$ so the formula for combination will be: \[ C\left(52, 5\right)=\frac{ 52!}{ 5! \left( 52 – 5 \right)!} \] Solving the above equation: \[ C\left(52, 5\right)=\frac{ 52!}{ 5! \times 47! } \] \[ C\left(52, 5\right) = 2,598,960 \] Now to find the number of hands with the queen of hearts in it. Let us suppose we have selected queen of hearts as one card, then the remaining will be $4$ cards left out of the $5 $ cards to be selected from the deck of $ 52$ cards. We have $n= 51 $ and $r = 4$ so the formula for combination will be: \[ C\left(51, 4\right)=\frac{ 51!}{ 4! \left( 51 – 4 \right)! } \] Solving the above equation: \[ C\left(51, 4\right)=\frac{ 51!}{ 4! \times 47! } \] \[ C\left(51, 4\right) = 249,900 \] Thus, the probability of not finding the queen of hearts in a five-card poker from a total of $52$ cards will be the possibility of the card divided by the total number of outcomes: \[ P(E) = \dfrac {249,900 }{ 2,598,960 } \] \[ P(E) = \dfrac {5 }{52 } \] Now putting the value of $P$ in the equation: \[ P\ (\vec{E})\ =\ 1\ -\ P(E)\] \[ P\ (\vec{E})\ =\ 1\ -\ \dfrac {5}{52}\] \[ P\ (\vec{E})\ =\ \dfrac {47}{52}\] \[ P\ (\vec{E})=0.9038 \]Numerical Results
Thus, the probability of not finding the queen of hearts in a five-card poker from a total of $52$ cards will be: \[ P\ (\vec{E})\ =\ \dfrac {47}{ 52}\]Example
A group of $4$ players is $P$, $Q$, $R$, $S$. In how many ways can a team of $2$ members be formed? Using the Combination formula: $n=4$ $r=2$ \[C\left(4,2 \right)=\frac{4!}{2!\left(4-2\right)!}\] \[C\left(4,2 \right)=6\]Previous Question < > Next Question
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