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# Chords of a Circle â€“ Explanation & Examples

*In this article, you’ll learn:*

- What a chord of a circle is.
- Properties of a chord and; and
- How to find the length of a chord using different formulas.

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## What is the Chord of a Circle?

**By definition, a chord is a straight line joining 2 points on the circumference of a circle. The diameter of a circle is considered to be the longest chord because it joins to points on the circumference of a circle.**

In the circle below, AB, CD, and EF are the chords of the circle. Chord CD is the diameter of the circle.

### Properties of a Chord

- The radius of a circle is the perpendicular bisector of a chord.

- The length of a chord increases as the perpendicular distance from the center of the circle to the chord decreases and vice versa.
- The diameter is the longest chord of a circle, whereby the perpendicular distance from the center of the circle to the chord is zero.
- Two radii joining the ends of a chord to the center of a circle form an isosceles triangle.

- Two chords are equal in length if they are equidistant from the center of a circle. For example, chord
*AB*is equal to chord*CD*if*PQ = QR.*

## How to Find the Chord of a Circle?

There are two formulas to find the length of a chord. Each formula is used depending on the information provided.

**The length of a chord, given the radius and distance to the center of a circle.**

If the length of the radius and distance between the center and chord is known, then the formula to find the length of the chord is given by,

**Length of chord = 2âˆš (r ^{2} â€“ d^{2})**

Where r = the radius of a circle and d = the perpendicular distance from the center of a circle to the chord.

In the above illustration, the length of chord *PQ =* 2âˆš (r^{2} â€“ d^{2})

**The length of a chord, given the radius and central angle**

If the radius and central angle of a chord are known, then the length of a chord is given by,

**Length of a chord = 2 Ã— r Ã— sine (C/2)**

**= 2r sine (C/2)**

Where r = the radius of the circle

C = the angle subtended at the center by the chord

d = the perpendicular distance from the center of a circle to the chord.

Letâ€™s work out a few examples involving the chord of a circle.

*Example 1*

The radius of a circle is 14 cm, and the perpendicular distance from the chord to the center is 8 cm. Find the length of the chord.

__Solution__

Given radius, r = 14 cm and perpendicular distance, d = 8 cm,

By the formula, Length of chord = 2âˆš(r^{2}âˆ’d^{2})

Substitute.

Length of chord = 2âˆš (14^{2}âˆ’8^{2})

= 2âˆš (196 âˆ’ 64)

= 2âˆš (132)

= 2 x 11.5

= 23

So, the length of the chord is 23 cm.

*Example 2*

The perpendicular distance from the center of a circle to the chord is 8 m. Calculate the chord’s length if the circle’s diameter is 34 m.

__Solution__

Given the distance, d = 8 m.

Diameter, D = 34 m. So, radius, r = D/2 = 34/2 = 17 m

Length of chord = 2âˆš(r^{2}âˆ’d^{2})

By substitution,

Length of chord = 2âˆš (17^{2 }âˆ’ 8^{2})

= 2âˆš (289 â€“ 64)

= 2âˆš (225)

= 2 x 15

= 30

So, the length of the chord is 30 m.

*Example 3*

The length of a chord of a circle is 40 inches. Suppose the perpendicular distance from the center to the chord is 15 inches. What is the radius of the chord?

__Solution__

Given, length of chord = 40 inches.

Distance, d = 15 inches

Radius, r =?

By the formula, Length of chord = 2âˆš(r^{2}âˆ’d^{2})

40 = 2âˆš (r^{2 }âˆ’ 15^{2})

40 = 2âˆš (r^{2 }âˆ’ 225)

Square both sides

1600 = 4 (r^{2} â€“ 225)

1600 = 4r^{2} â€“ 900

Add 900 on both sides.

2500 = 4r^{2}

Dividing both sides by 4, we get,

r^{2} = 625

âˆšr^{2} = âˆš625

r = -25 or 25

Length can never be a negative number, so we pick positive 25 only.

Therefore, the radius of the circle is 25 inches.

*Example 4*

Given that radius of the circle shown below is 10 yards and the length of *PQ* is 16 yards. Calculate the distance *OM*.

__Solution__

PQ = length of chord = 16 yards.

Radius, r = 10 yards.

OM = distance, d =?

Length of chord = 2âˆš(r^{2}âˆ’d^{2})

16 =2âˆš (10 ^{2}âˆ’ d ^{2})

16 =2âˆš (100 âˆ’ d ^{2})

Square both sides.

256 = 4(100 âˆ’ d ^{2})

256 = 400 âˆ’ 4d^{2}

Subtract 400 on both sides.

-144 = âˆ’ 4d^{2}

Divide both sides by -4.

36 = d^{2}

d = -6 or 6.

Thus, the perpendicular distance is 6 yards.

*Example 5:*

Calculate the length of the chord *PQ* in the circle shown below.

Solution

Given the central angle, C = 80^{0}

The radius of the circle, r = 28 cm

Length of chord *PQ *=?

By the formula, length of chord = 2r sine (C/2)

Substitute.

Length of chord = 2r sine (C/2)

= 2 x 28 x Sine (80/2)

= 56 x sine 40

= 56 x 0.6428

= 36

Therefore, the length of the chord *PQ* is 36 cm.

*Example 6*

Calculate the length of the chord and the central angle of the chord in the circle shown below.

__Solution__

Given,

Perpendicular distance, d = 40 mm.

Radius, r = 90 mm.

Length of chord = 2âˆš(r^{2}âˆ’d^{2})

= 2âˆš (90^{2 }âˆ’ 40^{2})

= 2 âˆš (8100 âˆ’ 1600)

= 2âˆš6500

= 2 x 80.6

= 161.2

So, the length of the chord is 161.2 mm

Now calculate the angle subtended by the chord.

Length of chord = 2r sine (C/2)

161.2 = 2 x 90 sine (C/2)

161.2 = 180 sine (C/2)

Divide both sides by 180.

0.8956 = sine (C/2)

Find the sine inverse of 0.8956.

C/2 = 63.6 degrees

Multiply both sides by 2

C = 127.2 degrees.

So, the central angle subtended by the chord is 127.2 degrees.