# Maclaurin Series – Definition, Expansion Form, and Examples

The Maclaurin series is another important power series that you’ll learn and understand in calculus. This series allows us to find an approximation for a given function, $f(x)$. With its extensive applications in numerical methods and applied mathematics, it essential that we understand the Maclaurin series.

The Maclaurin series is a power series that uses successive derivatives of the function and the values of these derivatives when the input is equal to zero. In fact, the Maclaurin series is a special type of the Taylor series.

Our discussion focuses on what makes this power series unique. We’ll also cover the conditions we need to find the Maclaurin series representing different functions. Since this series is closely related to the Taylor series, keep your notes on this topic handy as well. By the end of the article, you’ll learn how to rewrite familiar functions in their Maclaurin series form!

## What is a Maclaurin series?

The Maclaurin series is another polynomial approximation of a function. In fact, it is a special case of a Taylor series where each of the successive derivatives is evaluated at $x = 0$.  Simply put, the Maclaurin series is the Taylor series of the function at $x = 0$.

 Examples of Maclaurin series \begin{aligned}\boldsymbol{e^x }&= \boldsymbol{\sum_{n = 0}^{\infty} \dfrac{x^n}{n!}} \\&= \boldsymbol{1+ \dfrac{x}{1!} + \dfrac{x^2}{2!} + \dfrac{x^3}{3!}+ …}\\\boldsymbol{\sin x }&= \boldsymbol{(-1)^n\sum_{n = 0}^{\infty} \dfrac{x^{2n + 1}}{(2n)!}} \\&= \boldsymbol{x – \dfrac{x^3}{3!} + \dfrac{x^5}{5!} – \dfrac{x^{7}}{7!}+ …}\\\boldsymbol{\dfrac{1}{1 – x}}&= \boldsymbol{\sum_{n = 0}^{\infty} x^n} \\&= \boldsymbol{1+ x + x^2 + x^3 + …} \end{aligned}

These are just three examples of functions along with their Maclaurin series. The first equation shows the Maclaurin series of each of the functions in sigma notation while the second highlights the first three terms of each of the series.

### Understanding the Maclaurin series formula

As we have mentioned, the Maclaurin series is a special case of the Taylor series. Let’s begin by recalling the general form of the function’s Taylor series.

\begin{aligned} f(x) &= \sum_{n = 0}^{\infty} \dfrac{f^{(n)}(c)}{n!} (x – c)^n \\&= f(c) + \dfrac{f^{\prime}(c)}{1!}( x – c) + \dfrac{f^{\prime\prime}(c)}{2!}( x – c)^2 + \dfrac{f^{\prime\prime\prime}(c)}{3!}( x – c)^3 + …\end{aligned}

The Maclaurin series formula is simply the resulting expression when $\boldsymbol{c = 0}$. Hence, we have the Maclaurin series formula as shown below.

 MACLAURIN SERIES FORMULA \begin{aligned} f(x) &= \sum_{n = 0}^{\infty} \dfrac{f^{(n)}(0)}{n!} x^n \\&= f(0) + \dfrac{f^{\prime}(0)}{1!}x + \dfrac{f^{\prime\prime}(0)}{2!} x^2 + \dfrac{f^{\prime\prime\prime}(0)}{3!} x^3 + …\end{aligned}

This means that we can find the polynomial approximation for the function, $f(x)$, using the Maclaurin series and the succeeding derivatives of $f(x)$ evaluated at $0$.

## How to find a Maclaurin series?

Now that we know the general form of the Maclaurin series, we can try writing the Maclaurin series of different functions. Before we do so, check out the following pointers that may help you:

• Take the three succeeding derivatives of $f(x)$.
• Feel free to find more terms by differentiating the succeeding expressions as well.
• Evaluate $f(x)$, $f^{\prime}(x)$, $f^{\prime \prime}(x)$, $f^{\prime \prime \prime}(x)$, and more at $x = 0$.
• Write down the functions’ Maclaurin series by adding the resulting terms.

To check our current understanding, why don’t we confirm that $f(x) = e^x$ is equal to $1+ \dfrac{x}{1!} + \dfrac{x^2}{2!} + \dfrac{x^3}{3!}+ …$? We can also confirm that the Maclaurin series’ sigma notation is $\sum_{n = 0}^{\infty} \dfrac{x^n}{n!}$.

Let’s begin by differentiating $e^x$ three times in a row using the derivative rule, $\dfrac{d}{dx} e^x$. Afterwards, evaluate $f(0)$, $f^{\prime}(0)$, $f^{\prime \prime}(0)$, and $f^{\prime \prime \prime}(0)$.

 \begin{aligned}\boldsymbol{f^{(n)} (x)}\end{aligned} \begin{aligned}\boldsymbol{f^{(n)}(0)}\end{aligned} \begin{aligned}f(x) &= e^x\end{aligned} \begin{aligned}f(0) &= 1\end{aligned} \begin{aligned}f^{\prime}(x) &= e^x\end{aligned} \begin{aligned}f^{\prime}(0) &= 1\end{aligned} \begin{aligned}f^{\prime \prime}(x) &= e^x\end{aligned} \begin{aligned}f^{\prime \prime}(0) &= 1\end{aligned} \begin{aligned}f^{\prime \prime \prime}(x) &= e^x\end{aligned} \begin{aligned}f^{\prime \prime \prime}(0) &= 1\end{aligned} \begin{aligned}. \\. \\.\end{aligned} \begin{aligned}. \\. \\.\end{aligned} \begin{aligned}f^{(n)} (x) &= e^x\end{aligned} \begin{aligned}f^{(n)} (0) &= 1\end{aligned}

Substitute these expressions into the Maclaurin series formula to find the approximation for $y = e^x$.

\begin{aligned} e^x &= f(0) + \dfrac{f^{\prime}(0)}{1!}x + \dfrac{f^{\prime\prime}(0)}{2!} x^2 + \dfrac{f^{\prime\prime\prime}(0)}{3!} x^3 + …\dfrac{f^{(n)}(0)}{n!}+ …\\&=1  + \dfrac{1}{1!}x + \dfrac{1}{2!}x^2 + \dfrac{1}{3!}x^3 + …+ \dfrac{1}{n!}x^n+ …\\&= 1 + x + \dfrac{x^2}{2} + \dfrac{x^3}{6} + … +\dfrac{x^n}{n!}+…\end{aligned}

We can write this series in sigma notation using the $n$th term of the Maclaurin series. Hence, we have $f(x) = e^x = \sum_{n = 0}^{\infty} \dfrac{x^n}{n!}$. Apply a similar process when writing the Maclaurin series of different functions. When you’re ready, head over to the sample problems below to master this topic!

Example 1

Find the Maclaurin series of $f(x) = \sin x$ up to its fourth-order then write the Maclaurin series in sigma notation.

Solution