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Foil Method to Distribute Two Binomials – Explanation & Examples

What is the Foil Method?

Many students will start thinking of a kitchen when they first hear a mention of the term foil.

Here, we are talking about the FOIL – a mathematical series of steps used multiply two binomials. Before we learn what the term foil entails, let’s take a quick review of what the word binomial is.

A binomial is simply an expression that consist of two variables or terms which are separated by either addition sign (+) or subtraction sign (-). Examples of binomial expressions are 2x + 4, 5x + 3, 4y – 6, – 7y – y etc.

How to do Foil Method?

The foil method is a technique used for remembering the steps required to multiply two binomials in an organized manner.

The F-O-I- L acronym stands for first, outer, inner and last.

Let’s explain each of these terms with the help of bold letters:

  • First, which means, multiplying the first terms together i.e. (a + b) (c + d)
  • Outer means that, the we multiply the outermost terms when the binomials are place side by side i.e. (a + b) (c + d).
  • Inner means multiply the innermost terms together i.e. i.e. (a + b) (c + d).
  • Last. This implies that, we multiply together the last term in each binomial i.e. i.e. (a + b) (c + d).

How do you distribute binomials using foil method?

Let us put this method into perspective by multiplying two binomials, (a + b) and (c + d).

To find multiply (a + b) * (c + d).

  • Multiply the terms which appear in the first position of binomial. In this, case a and c are the terms and their product are;

(a *c) = ac

  • Outer(O) is the next word after the word first(F), therefore, multiply the outermost or the last terms when the two binomials are written side by side. The outermost terms are b and d.

(b * d) = bd

  • The term inner implies that we multiply two terms that are in middle when the binomials are written side-by-side;

(b * c) = bc

  • The last implies that we find the product of the last terms in each binomial. The last terms are b and d, therefore, b * d = bd

Now we can sum up the partial products of the two binomials beginning from the first, outer, inner and then the last. Therefore, (a + b) * (c + d) = ac + ad + bc + bd.

The foil method is an effective technique because it can be used to manipulate numbers, irregardless of how they might look ugly with fractions and negative signs.

How do you multiply binomials using foil method?

In order to master the foil method better, we shall solve a few examples of binomials.

Example 1

Multiply (2x + 3) (3x – 1)

Solution

  • Begin, by multiplying together, the first terms of each binomial

= 2x * 3x = 6x 2

  • Now multiply the outer terms.

= 2x * -1= -2x

  • Now multiply the inner terms.

= (3) * (3x) = 9x

  • Finally multiply the last team in each binomial together.

= (3) * (–1) = –3

  • Sum up the partial products starting from the first to last product and collect the like terms;

= 6x 2 + (-2x) + 9x + (-3)

= 6x 2 + 7x – 3.

Example 2

Use the foil method to solve:(-7x−3) (−2x+8)

Solution

  • Multiply the firstterms;

= -7x * -2x = 14x 2

  • Multiply the outer terms;

= -7x * 8 = -56x

  • Multiply the inner terms of the binomials;

= – 3 * -2x = 6x

  • Finally, multiply the last terms;

= – 3 * 8 = -24

  • Find the sum of the partial products and collect the like terms;

= 14x 2 + ( -56x) + 6x + (-24)

= 14x 2 – 56x – 24

Example 3

Multiply (x – 3) (2x – 9)

Solution

  • Multiply the first terms together;

= (x) * (2x) = 2x 2

  • Multiply the outermost terms of each binomial;

= (x) *(–9) = –9x

  • Multiply the inner terms of the binomials;

= (–3) * (2x) = –6x

  • Multiply the last terms of each binomial;

= (–3) * (–9) = 27

  • Sum up the products following the foil order and collect the like terms;

= 2x 2 – 9x -6x + 27

= 2x 2 – 15x +27

Example 4

Multiply [x + (y – 4)] [3x + (2y + 1)]

Solution

  • In this case, the operations are broken down into smaller units and the results combine;
  • Begin by multiplying the first terms;

= (x) * 3x = 3x 2

  • Multiply the outer terms of each binomial;

= (x) * (2y + 1) = 2xy + x

  • Multiply the inner terms of each binomial;

= (y – 4) (3x) = 3xy – 12x

  • Now finish by multiplying the last terms

= (y – 4) (2y + 1)

Since the last terms area gain two binomials; Sum up the products;

= 3x 2 + 2xy + x + 3xy – 12x +(y – 4) (2y + 1)

= 3x 2 + 5xy – 11x + (y – 4) (2y + 1)

Again, apply the foil method on (y – 4) (2y + 1).

  • (y) * (2y) = 2y2
  • (y) *(1) = y
  • (–4) * (2y) = –8y
  • (–4) * (1) = –4

Sum up the totals and collect the like terms;

= 2y2 – 7y – 4

Now replace this answer into the two binomials;

= 3x 2 + 5xy – 11x + (y – 4) (2y + 1) = 3x 2 + 5xy – 11x + 2y2 – 7y – 4

Therefore,

[x + (y – 4)] [3x + (2y + 1)] = 3x 2 + 5xy – 11x + 2y2 – 7y – 4

Practice Questions

Multiply the following binomials using the foil method:

  1. (- x−1) (−x+1).
  2. (4x+5) (x+1)
  3. (3x−7) (2x+1)
  4. (x+5) (x−3)
  5. (x−12) (2x+1).
  6. (10x−6) (4x−7)

Answers

  1. x 2– 1
  2. – 4x2 + x +5
  3. 6x2 -11x -7
  4. x 2 + 2x -15
  5. 2x2 -23x – 12
  6. – 40x2 +46x +42

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