This question explains the method to calculate the **total positive charge** inside the **nuclei** of any gas.

Every gas has a different **positive charge** inside its nucleus and the total number of protons also differs for every gas. The **number of protons** is called the atomic number, which differentiates all the **elements** of the **periodic table.**

The **positive charge** on each **proton** is the same for every **gas.** The total charge will be the sum of the **charge** on all **protons** contained in the gas.

## Expert Answer

The **total positive charge** in the nucleus of any gas is the total number of protons times the total **charge** contained by **one proton.** The total **number** of **protons** depends on the type of gas, for example, **hydrogen, oxygen, chlorine,** etc. Each gas has a different number of **protons** in its **nuclei.**

To calculate the total **positive charge** in the **atomic nuclei** of any gas, find the total number of atoms in the gas. It can be calculated by multiplying **Avogadro’s Number** $N_A$ with the total amount of gas in moles. If the gas is available in molecules like **$O_2, F_2, Cl_2$,** then it needs to be multiplied by **2** to calculate the correct number of **atoms** in the gas. The **total number** of **protons** needs to be calculated, which can be done by multiplying the **atomic number** of gas with the total number of atoms calculated before. Now we can calculate the **charge** by multiplying the charge on one **proton** by the total **number** of **protons.**

Suppose we need to find the total **positive charge** in **1 mole** of **$O_2$** gas. Now we need to find the total number of **atoms** in **1 mole** of **$O_2$** gas. **$O_2$** has 2 atoms in each **molecule,** so we would need to incorporate this in our calculations.

**AmountÂ ofÂ Gas, n = 1 mols**

**AtomsÂ inÂ 1Â molecule, m = 2Â atoms**

**ProtonsÂ inÂ 1Â atom, P = 8**

**ChargeÂ onÂ 1Â Proton, e = 1.6 x $10^{-19}$ C**

**Avogadro’sÂ Constant, N_A = 6.022 x $10^{23}$ **

**TotalÂ NumberÂ ofÂ Atoms, N = n x m x $N_A$ **

** N = 1 x 2 x 6.022 x $10^{23}$**

** N = 1.2 x $10^{24}$**

**TotalÂ NumberÂ ofÂ Protons,Â $T_p$ = N x P **

** $T_p$ = 1.2 x $10^{24}$ x 8 **

** $T_p$ = 9.6 x $10^{24}$**

## Numerical Result

**TotalÂ Charge, Q = Tp x e**

**Q = 9.6 x $10^{24}$ x 1.6 x $10^{-19}$**

**Q = 1.54 x $10^6$ C**

## Example

Suppose we need to find the total positive charge in **Fluorine(F) gas nuclei.** We take only one atom of **F gas** to calculate the **positive charge** in its **nucleus.**

**AtomicÂ NumberÂ ofÂ Fluorine,Â Z = 9**

**ChargeÂ onÂ 1Â Proton, e = 1.6 x $10^{-19}$ C**

**TotalÂ Charge, Q = Z x e**

**Q = 9 x 1.6 $10^{-19}$ C**

**Q = 1.44 x $10^{-18}$ C**

The total charge in the atomic nuclei of Fluorine gas is $1.44 \times 10^{-18} C$. As we have the positive atomic charge of one atom of **F gas,** we can now calculate the **positive charge** for any given amount of gas. For example, if we are given $1$ mol of **F** gas, and we need to find the total positive charge, we simply need to find the total **number** of **atoms** in **1 mol of F gas** and multiply it with the charge in one atom.

**AmountÂ ofÂ Gas, n = 1 mols**

**Avogadro’sÂ Constant, $N_A$ = 6.022 x $10^{23}$**

**TotalÂ NumberÂ ofÂ Atoms, N = n x m x $N_A$**

**N = 1 x 6.022 x $10^{23}$**

**N = 6.022 x $10^{23}$**

**Total Charge, $Q_t$ = N x Q**

**$Q_t$ = 6.022 x $10^{23}$ x 1.44 x $10^{-18}$ C**

**$Q_t$ = 8.7 x $10^5$ C**