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# Simplifying Expressions – Explanation & Examples

Learning how to simplify expression is the most important step in understanding and mastering algebra. Simplification of expressions is a very useful mathematics skill because, it allows us to change complex or awkward expression into more simple and compact form. But before that we must know what an algebraic expression is.

An algebraic expression is a mathematical phrase where variables and constants are combined using the operational (+, -, × & ÷) symbols. For example, 10x + 63 and 5x – 3 are examples of algebraic expressions.

In this article we shall learn a few tricks on **how to simplify any algebraic expression.**

## How to Simplify Expressions?

Simplification of an algebraic expression can be defined as the process of writing an expression in the most efficient and compact form without affecting the value of the original expression.

The process entails collecting like terms, which implies, adding or subtracting terms in an expression.

*Let’s remind ourselves some the important terms used when simplifying an expression:*

- A variable is a letter whose value is unknown to in algebraic expression.
- The coefficient is a numerical value used together with a variable.
- A constant is a term which has a definite value.
- Like terms are variables with same letter and power. Like terms can sometimes contain different coefficients. For example, 6x
^{2}and 5x^{2}are like terms because both of them have the variable with a similar exponent. Similarly, 7yx and 5xz are unlike terms because each term has different variables.

*To simplify any algebraic expression, the following are the basic rules and steps:*

- Remove any grouping symbol such as brackets and parentheses by multiplying factors.
- Use the exponent rule to remove grouping if the terms are containing exponents.
- Combine the like terms by addition or subtraction
- Combine the constants

*Example 1*

Simplify 3*x*^{2} + 5*x*^{2}

__Solution__

Since both terms in the expression are have same exponents, we combine them;

3*x*^{2} + 5*x*^{2} = (3 + 5)* x*^{2} = 8*x*^{2}

*Example 2*

Simplify the expression: 2 + 2x [2(3x+2) +2)]

__Solution__

First work out any terms within brackets by multiplying them out;

= 2 + 2x [6x + 4 +2] = 2 + 2x [6x + 6]

Now eliminate the parentheses by multiplying any number outside it;

2 + 2x [6x + 6] = 2 + 12x ^{2 }+ 12x

This expression can be simplified by dividing each term by 2 as;

12x ^{2}/2 + 12x/2 + 2/2 = 6 x ^{2} + 6x + 1

*Example 3*

Simplify 3*x* + 2(*x* – 4)

__Solution__

In this case, it is impossible to combine terms when they are still in parentheses or any grouping sign. Therefore, get rid of the parenthesis by multiplying any factor outside the grouping by all terms inside it.

Hence, 3*x* + 2(*x* – 4) = 3*x* + 2*x* – 8

= 5*x* – 8

When a minus sign is in front of a grouping, it normally affects all the operators inside the parentheses. This means that a minus sign in front of a group will change addition operation to subtraction and vice versa.

*Example 4*

Simplify 3*x* – (2 – *x*)

__Solution__

3*x* – (2 – *x*) = 3*x* + (–1) [2 + (–*x*)]

= 3*x* + (–1) (2) + (–1) (–*x*)

= 3*x* – 2 + *x*

= 4*x* – 2

However, if there is only a plus sign comes before the grouping, then the parentheses are simply erased.

**For example**, to simplify 3*x* + (2 – *x*), the brackets are eliminated as shown below:

3x + (2 – x) = 3x + 2 – x

*Example 5*

Simplify 5(3x-1) + x((2x)/ (2)) + 8 – 3x

__Solution__

15x – 5 + x(x) + 8 – 3x

15x – 5 + x^{2} + 8 – 3x.

Now combine the like terms by adding and subtracting the terms;

x^{2} + (15x – 3x) + (8 – 5)

x^{2} + 12x + 3

*Example 6*

Simplify x (4 – x) – x (3 – x)

__Solution__

x (4 – x) – x (3 – x)

4x – x^{2} – x (3 – x)

4x – x^{2} – (3x – x^{2})

4x – x^{2} – 3x + x^{2} = x

*Practice Questions*

Simplify each of the following expressions:

- 2st + 3t – s + 5t + 4s
- 2a – 4b +3ab -5a +2b
- x (2x + 3y -4) – x
^{ 2}+ 4xy – 12 - 4(2x+1) – 3x
- 4(p – 5) +3(p +1)
- [2x
^{3}y^{2}]^{3} - 6(p +3q) – (7 +4q)
- 4rs -2s – 3(rs +1) – 2s
- [ (3 – x) (x + 2) + (-x + 4) (7x + 2) – (x – y) (2x – y)] – 3x
^{2}– 7x + 5

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