 # Factors of 525: Prime Factorization, Methods, and Examples

The numbers that result in 525 when these two numbers are multiplied together are the factors of 525. These two numbers work as a factor pair when combined. Given that the given number is obtained by multiplying integers with two factors, its factors may be both positive and negative.

### Factors of 525

Here are the factors of number 525.

Factors of 525: 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175 and 525

### Negative Factors of 525

The negative factors of 525 are similar to their positive aspects, just with a negative sign.

Negative Factors of 525: -1, -3, -5,- 7, -15, -21, -25, -35,- 75, -105, -175 and -525

### Prime Factorization of 525

The prime factorization of 525 is the way of expressing its prime factors in the product form.

Prime Factorization:31 x 52 x 71

In this article, we will learn about the factors of 525 and how to find them using various techniques such as upside-down division, prime factorization, and factor tree.

## What Are the Factors of 525?

The factors of 525 are 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175 and 525. These numbers are the factors as they do not leave any remainder when divided by 525.

The factors of 525 are classified as prime numbers and composite numbers. The prime factors of the number 525 can be determined using the prime factorization technique.

## How To Find the Factors of 525?

You can find the factors of 525 by using the rules of divisibility. The divisibility rule states that any number, when divided by any other natural number, is said to be divisible by the number if the quotient is the whole number and the resulting remainder is zero.

To find the factors of 525, create a list containing the numbers that are exactly divisible by 525 with zero remainders. One important thing to note is that 1 and 525 are the 525’s factors as every natural number has 1 and the number itself as its factor.

1 is also called the universal factor of every number. The factors of 525 are determined as follows:

$\dfrac{ 525}{1} = 525$

$\dfrac{ 525}{3} = 175$

$\dfrac{ 525}{5} = 105$

$\dfrac{ 525}{ 7} = 75$

$\dfrac{ 525}{15} = 35$

$\dfrac{ 525}{21} = 25$

$\dfrac{ 525}{25} = 21$

$\dfrac{ 525}{ 35} = 15$

$\dfrac{ 525}{75} = 7$

$\dfrac{ 525}{105} = 5$

$\dfrac{ 525}{175} = 3$

$\dfrac{ 525}{ 525} = 1$

Therefore, 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175 and 525.

### Total Number of Factors of 525

For 525, there are12 positive factors and 12 negative ones. So in total, there are 24 factors of 525.

To find the total number of factors of the given number, follow the procedure mentioned below:

1. Find the factorization/prime factorization of the given number.
2. Demonstrate the prime factorization of the number in the form of exponent form.
3. Add 1 to each of the exponents of the prime factor.
4. Now, multiply the resulting exponents together. This obtained product is equivalent to the total number of factors of the given number.

By following this procedure, the total number of factors of 525 is given as:

Factorization of 525 is 31 x 52 x 71.

The exponent of 3 is 1, 5 is 2, and 7 is 1.

Adding 1 to each and multiplying them together results in 24.

Therefore, the total number of factors of 525 is 24. 12 are positive, and 12 factors are negative.

### Important Notes

Here are some essential points that must be considered while finding the factors of any given number:

• The factor of any given number must be a whole number.
• The factors of the number cannot be in the form of decimals or fractions.
• Factors can be positive as well as negative.
• Negative factors are the additive inverse of the positive factors of a given number.
• The factor of a number cannot be greater than that number.
• Every even number has 2 as its prime factor, the smallest prime factor.

## Factors of 525 by Prime Factorization

The number 525 is a composite number. Prime factorization is a valuable technique for finding the number’s prime factors and expressing the number as the product of its prime factors. Before finding the factors of 525 using prime factorization, let us find out what prime factors are. Prime factors are the factors of any given number that are only divisible by 1 and themselves.

To start the prime factorization of 525, start dividing by its most minor prime factor. First, determine that the given number is either even or odd. If it is an even number, then 2 will be the smallest prime factor.

Continue splitting the quotient obtained until 1 is received as the quotient. The prime factorization of 525 can be expressed as:

525=31 x 52 x 71

## Factors of 525 in Pairs

The factor pairs are the duplet of numbers that, when multiplied together, result in the factorized number. Factor pairs can be more than one depending on the total number of factors given. For 525, the factor pairs can be found as:

1 x 525 = 525

3 x 175= 525

5 x 105 = 525

7 x 75 = 525

15 x 35 = 525

21 x 25 = 525

The possible factor pairs of 525 are given as (1, 525),(3, 175),(5, 105),(7, 75),(15, 35) and (21, 25).

All these numbers in pairs, when multiplied, give 525 as the product.

The negative factor pairs of 525 are given as:

-1 x – 525 = 525

-3 x -175= 525

-5 x -105 = 525

-7 x -75 = 525

-15 x -35 = 525

-21 x -25 = 525

It is important to note that in negative factor pairs, the minus sign has been multiplied by the minus sign, due to which the resulting product is the original positive number. Therefore, -1, -3, -5,- 7, -15, -21, -25, -35,- 75, -105, -175 and -525 are called negative factors of 525.

The list of all the factors of 525, including positive as well as negative numbers, is given below.

Factor list of 525: 1,-1, 3,-3,5, -5, 7,- 7,15, -15, 21,-21, 25,-25,35, -35,75,- 75, 105,-105, 175,-175 , 525, and – 525,

## Factors of 525 Solved Examples

To better understand the concept of factors, let’s solve some examples.

### Example 1

How many factors of 525 are there?

### Solution

The total number of Factors 525 is 24.

Factors of  525 are 1, 3, 5, 7, 15, 21, 25, 35, 75, 105, 175 and 525.

### Example 2

Find the factors of 525 using prime factorization.

### Solution

The prime factorization of 525 is given as:

525 $\div$ 3 = 175

175 $\div$ 5 = 35

35 $\div$ 5 = 7

7 $\div$ 7 = 1

So the prime factorization of 525 can be written as:

31 x 52 x 71 = 525