Contents

# What Is 20/23 as a Decimal + Solution With Free Steps

**The fraction 20/23 as a decimal is equal to 0.869.**

**Decimals** and **Fractions **are two methods for expressing any number. These two kinds can be converted into one another.Â A number is expressed in fractional form as the ratio of two non-zero values and in decimal form, as a number having a decimal point.

Here, we are more interested in the division types that result in a **Decimal** value, as this can be expressed as a **Fraction**. We see fractions as a way of showing two numbers having the operation of **Division** between them that result in a value that lies between two **Integers**.

Now, we introduce the method used to solve said fraction to decimal conversion, called **Long Division,Â **which we will discuss in detail moving forward. So, letâ€™s go through the **Solution** of fraction **20/23**.

## Solution

First, we convert the fraction components, i.e., the numerator and the denominator, and transform them into the division constituents, i.e., the **Dividend** and the **Divisor,** respectively.

* This can be done as follows:*

**Dividend = 20**

**Divisor = 23**

Now, we introduce the most important quantity in our division process: theÂ **Quotient**. The value represents the **Solution** to our division and can be expressed as having the following relationship with the **Division** constituents:

**Quotient = Dividend $\div$ Divisor = 20 $\div$ 23**

This is when we go through the **Long Division** solution to our problem, which can be seen in figure 1.

## 20/23 Long Division Method

We start solving a problem using the **Long Division Method** by first taking apart the divisionâ€™s components and comparing them. As we have **20**Â and **23,** we can see how **20** is **Smaller** than **23**, and to solve this division, we require that 20 be **Bigger** than 23.

This is done by **multiplying** the dividend by **10** and checking whether it is bigger than the divisor or not. If so, we calculate the Multiple of the divisor closest to the dividend and subtract it from the **Dividend**. This produces the **Remainder,** which we then use as the dividend later.

Now, we begin solving for our dividend **20**, which after getting multiplied by **10** becomes **200**.

*We take this 200 and divide it by 23; this can be done as follows:*

**Â 200 $\div$ 23 $\approx$ 8**

Where:

**23 x 8 = 184**

This will lead to the generation of a **Remainder** equal to **200 â€“ 184 = 16**. Now this means we have to repeat the process by **Converting** the **16** into **160**Â and solving for that:

**160 $\div$ 23 $\approx$ 6**

Where:

**23 x 6 = 138**

This, therefore, produces another **Remainder** which is equal to **160 â€“ 138 = 22**. Now we must solve this problem to **Third Decimal Place** for accuracy, so we repeat the process with dividend **220**.

**220 $\div$ 23 $\approx$ 9**

Where:

**23 x 9 = 207**

Finally, we have a **Quotient** generated after combining the three pieces of it as **0.869=z**, with a **Remainder** equal to **13**.

*Images/mathematical drawings are created with GeoGebra.*

#### 20/32 As A Decimal< Fractions to Decimals List > 18/32 As A Decimal

**What Is 3/12 as a Decimal + Solution With Free Steps**

**The fraction 3/12 as a decimal is equal to 0.25.**

**Fraction** is a term used to represent a small portion or piece of a whole object. For example, **1/4** means one-fourth of an object. If an object is divided into **4 **equal parts, then **1/4** is the magnitude or size of one part.

A fraction is made up of two elements, the denominator and the numerator. Decimal value of any fraction can be found by division of numerator and denominator. In mathematical calculations, it is difficult to use fractions because these can cause confusion and also can prolong calculations. The solution to this problem is to use decimal values instead of fractions. The **Decimal**** Value** of any fraction can be found by division of numerator and denominator. It is a numeric value containing a **Decimal Point**.

In this section, we will try to understand the **Long Division** method for converting any fraction into its decimal value.

**Solution**

To resolve a fraction, one should have a deep understanding of division. In division, there are two important components, the **Dividend, **and the **Divisor**. A dividend is a number, which has to be split into smaller parts. On the other hand, the divisor is the number splitting the dividend.

When a fraction is solved, its component numerator is considered a dividend while the denominator is considered a divisor. So, for **3/12**, we can write:

**Dividend = 3**

**Divisor = 12**

The decimal number or answer obtained after completing the process of division is called the **Quotient**.

** Quotient = Dividend $\div$ Divisor = 3 $\div$ 12**

A residual value at the end of the Division is called the **Remainder**. A non-zero value of remainder means that the number has not been completely divided.

Figure 1

**3/12 Long Division Method**

Nowadays, although the decimal value of any fraction can be determined using calculators in no time still it is necessary to learn the conventional division methods to solve the fractions. **Long Division** is an authentic method, which has no possibility of errors and provides us with accurate results.

Figure 1 shows the **Long Division** to solve **3/12**.

**3 $\div$ 12**

We know that the division process requires dividends to be larger than divisors. But we have **3** which is smaller than **12**, the divider. Thus, we add a zero to dividend **3 **to make it** 30** and a decimal point in the quotient.

**30 $\div$ 12 \approx 2**

**12 x 2 = 24**

A remaining value greater than zero is generated and is given as:

**30 â€“ 24 = 6**

This **6** is made 60 by its multiplication with 10 to divide by **12**.

**60 $\div$ 12 = 5**

**12 x 5 = 60**

As no residual is left behind so, **0.25** is determined decimal value of **3/12**. It tells us that when **12** parts, each of size **0.25** are combined, we get a value of **3**.

*Images/mathematical drawings are created with GeoGebra.*