**What Is 1 2/3 as a Decimal + Solution With Free Steps**

**The fraction 1 2/3 as a decimal is equal to 1.6666666666.**

To make **Fractions** easier to grasp, they are converted into **Decimal numbers**. Improper fractions, proper fractions, and mixed fractions are the three categories into which fractions can be divided. A fraction is Improper if the numerator is higher than the denominator. **A proper fraction** refers to a fraction whose numerator is less than its denominator. A fraction containing both a whole number and an Improper fraction is said to be a mixed**Â fraction**.

We must apply the division mathematical operator to turn fractions into their decimal equivalents. One of the most challenging mathematical operations is **Division**. By employing the **Long Division** approach, we can simplify this.

**Solution**

The mixed fraction needs to be changed into the **p/q** form. The fraction’s **p** is referred to as the **Numerator**, while its **q** is referred to as the **Denominator**. We will add **2** to the product while keeping the denominator constant and multiply the denominator **3** with the whole number **1** to obtain the numerator from the mixed fraction. This leaves us with a fraction of **5/3**.

**Dividend** and **Divisor** are the two main ideas in the long division method. **P** is referred to as the **dividend,** and **q** is referred to as the **divisor** in the fraction representation of **p/q**. The dividend and divider in this case are:

**Dividend = 5**

**Divisor = 3**

The solution of the fraction in decimal form is referred to as the **Quotient**.

**Quotient = Dividend $ \div $ Divisor = 5 $ \div $ 3**

The **long** **division** method for the given fraction is:

Figure 1

**5/3 Long Division Method**

The fraction we have is:

**5 $ \div $ 3**

Here, we can directly divide the two numbers because the dividend is greater than the divisor.

Another key term used in the long division method is “**Remainder**.” The number remains after the division of numbers that are not wholly divisible.

**5 $ \div $ 3 $ \approx $ 1**

Where:

**Â 3 x 1 = 3**

For the **remainder,** we have **5 – 3 = 2**. The remainder is less than the divisor, so to proceed further, we need to add zero to the right side of the remainder. For that, we will add a **decimal** **point** to the quotient. By doing so, now we have a new remainder of **20**.

Now we will divide **20** by the divisor of **3**, and we will get:

**20 $ \div $ 3 $ \approx $ 6**

Where:

**Â 3 x 6 = 18**

We now have a **remainder** of **20 – 18 = 2**. Again, we will add zero to the right side of the remainder, and we will get **20**.

**20 $ \div $ 3 $ \approx $ 6**

Where:

**Â 3 x 6 = 18**

Finally, we have a resulting **Quotient** of **1.66**, with a **RemainderÂ **of **2**.

*Images/mathematical drawings are created with GeoGebra.*