Work Calculator Physics + Online Solver With Free Steps
The Work Calculator Physics calculates the value of work done by using the inputs of force and distance entered by the user. Work describes the energy exerted in moving an object with applied force over a certain distance. Moreover, the force must be applied in the direction of the distance.
The calculator does not support the variables as input. You have to enter the values of force and distance in metric units. Furthermore, you have to calculate the effective force beforehand to make sure the force is in the direction of motion.
What Is the Work Calculator Physics?
The Work Calculator Physics is an online tool that uses the product of the two inputs, force and distance (in metric units), to find the value of the work done. Additionally, it provides a breakdown of the actual calculation along with the description of the units of work, force, and distance in metric units.
The calculator interface consists of two input boxes separately with the labels “force” and “distance.” All you have to do is enter the desired value of force and distance in the metric units to find the value of work.
How To Use the Work Calculator Physics?
You can utilize the Work Calculator Physics to find the work done on an object by simply entering the values of force and distance in the text boxes.
The guidelines for the calculator’s usage are below.
First of all, we have to make sure that the values of force and distance must be in metric units. That is the value for force must be in Newtons and the value for distance must be in meters. Moreover, we have to make sure that the force exerted is in the direction of the motion F = f cos$\theta$
Afterward, enter the desired values of the force and distance in their respective text boxes as labeled on the calculator interface.
Finally, press the Submit button to get the results.
The results of this calculator show up in a pop-up window on the same page and contain 4 sections:
- Input Interpretation: You will see the values entered as interpreted by the calculator. It lets you verify the correctness of the input and interpretation.
- Result: The value of the work done with its units in “joules.”
- Basic Dimensions: Dimensions of the two inputs and products in the form of basic dimensions, namely mass, length and time. This conveys the basic units of the work and further verifies the calculator’s results.
- Standard Units: This part shows the metric units used for the inputs i.e., force and distance.
How Does the Work Calculator Physics Work?
The Work Calculator Physics works by taking the product of the input force F and distance s to find the work done W. This is based on the definition of work itself.
Work done on an object is the force exerted on the object to move it in the direction of the force. The work done W is then the dot product of the inputs F and s.
W = F.s
W = Fs.cos$\theta$
Hence, we can see that work is also dependent on the angle difference between the force and the displacement covered by the object. Thus, we would always require the effective force exerted on the object and multiply it to find the correct work done by the force on the object.
An object is moved 15 meters by a force of 20 N, exerted in the same direction as the distance. Find the value of the work done on the object.
The input values of force and distance are:
F = 20N
s = 15m
As we do not need to calculate the effective distance of the object due to the force and distance having a zero angle difference, we can simply solve it by finding the product of the two inputs.
W = F.s
W = 20 . 15
W = 300J
Where W is work done, and J is the unit, joule, for work.
Consider a stationary object. A force of 25 N is exerted at an angle of 30 degrees to move it over a distance of 10 meters. Find the corresponding work done on the object.
In this example, we have a non-zero value of direction along with distance and force. Hence, for the calculation of work, we would need the effective force applied in the direction of the motion of the object. It can be done as below.
F = f cos$\theta$
F = 25 cos(30)
F = 21.651 N
Where F is the effective force exerted in the direction of the object’s displacement (approximated to 3 decimal places), and f is the total force exerted on the object.
Now, we calculate the product of F and s to find the Work W.
W = F.s
W = 21.651 . 10
W = 216.51 J
Where W is Work done, and J is the unit, joule, for work.
Suppose that a 50 N force is applied to an object “A” and it moves 20 meters at an angle of 60 degrees of the force. Find the work done on object A.
As done previously in example 2, we will first find the effective force applied on object A in the direction of the force by the following steps:
F = f cos$\theta$
F = 50 . cos(60)
F = 25 N
Finally, we find the product of F and s to find the work W.
W = F.s
W = 25 . 20
W = 500 J
Hence, the work done on object A is 500 J.