# What Is 1 1/3 as a Decimal + Solution With Free Steps

**The fraction 1 1/3 as a decimal is equal to 1.333.**

In a **complex fraction**, a fraction can be found in either the numerator or the denominator. A suitable fraction has a numerator that is less than its denominator.

It can also be stated as a mixed number, which is a whole-number quotient with a **proper-fraction** remainder, and is known as an **improper fraction** if the numerator is larger a repeating decimal, also known as a** recurring decimal**, is used to represent a number whose digits are periodic, repeating their values at regular intervals, and whose indefinitely repeated part is not **zero**.

To solve theÂ **1 1/3**Â fraction, theÂ **long division methodÂ **is recommended.

## Solution

The provided mixed fraction **1 1/3 is** first converted into an existing simple improper fraction by multiplying the denominator** 3** by the whole number** 1**, and then by adding a nominator 1 that happens to be equal to** 4/3**.

\[ 1 + \frac{1}{3} = \frac{4}{3}\]

To continue, we, first of all, take the **dividend** and the **divisor**Â from our given fraction. The steps are as follows:

**DividendÂ =Â 4**

**DivisorÂ = 3**

Recognizing that the **denominator** is the Divisor and the **numerator** is the Dividend. We may now go to the** quotient**, which is referred to as the solution to a division, with ease. Therefore, a quotient would appear as follows given the circumstances:

**Quotient=Dividend $\div$ Divisor = 4 $\div$ 3**

Here, we takeÂ **the**** long division method**Â to solve this fractionÂ **4/3**

Â Â Â Figure 1

## 1 1/3 Long Division Method

We have fractions:

**4 $\div$ 3Â **

We need to add a **decimal point** when the dividend is less than the divisor, which we may do by multiplying the dividend by **10**. Therefore, we don’t require any decimal points if the divisor is lower. 4/3is divided as illustrated in the instance below.

**4 $\div$ 3 $\approx$ 1**

Where:

** 3 x 1 = 3**

**4 â€“ 3 = 1Â **is the r**emainder** left after division.

Now we have dividend** 1** and the divisor is **3** which means we have to multiply the dividend by **10** as it is smaller than the divisor.

**10 $\div$ 3 $\approx$ 3**

Where:

**3 x 3 = 9**

We are left with the remainderÂ of **10** â€“ **9** = **1**

Our division is incomplete yet. we can see that remainderÂ **1** needÂ **zero** to solve further after multiplying remainderÂ **1**Â withÂ **10**Â our dividend becomes **10Â **And the divisor is**Â 3.**

**10 $\div$ 3 $\approx$ 3**

Where:

** 3 x 3 = 9**

Again the remainder is **10** â€“ **9** = **1**

As the remainder is**Â 1, **again it will become**Â 10Â **and we will divide it by**Â 3.**

**Â 10 $\div$ 3 $\approx$ 3**

Â Where:

** 3 x 3 = 9**

Again the remainder is **10** â€“ **9** = **1**

**As** this is a recurring number, after three iterations we stop here with remainder **1 **and a quotient of **1.333** obtained.

*Images/mathematical drawings are created with GeoGebra*