# What Is 15/16 as a Decimal + Solution With Free Steps

**The fraction 15/16 as a decimal is equal to 0.9375.**

We are aware that fractions are of two types, one is **Proper**, and the other is **Improper**. A **Proper Fraction** is one where the numerator is smaller than the denominator, and the **Improper** is the one where the denominator is bigger than the numerator.

Both these fractions will result in a **Decimal Value**, but the improper one would produce a whole number bigger than 0. We have a fraction of 15/16 which is **Proper**, so it will produce a whole number of 0.

A **Whole Number** in a fraction is the non-decimal part of the fraction. Now, letâ€™s look at the solution to our fraction in detail.

## Solution

First, we take the Dividend and the Divisor out of our fraction:

**Dividend = 15**

**Divisor = 16**

Where a **Dividend** is a numerator being divided, and the **Divisor** is the denominator that divides.

Now, we move forward by introducing the **Quotient**, which is the result of a division. But for a fraction that cannot be solved further using the **Multiple Method**, we use another method. This method is called **Long Division**, and we begin by expressing our transformed fraction as a division:

**Quotient = Dividend $\div$ Divisor = 15 $\div$ 16**

Now, letâ€™s dive deeper into the **Long Division** solution of the fraction 15/16:

Figure 1

### 15/16 Long Division Method

We start by discussing the number called the **Remainder**, which is what remains when an **Inconclusive Division** occurs. It is important because it will become the new dividend as we move forward in solving the division.

**Long Division** generally works by introducing a **Decimal Point** in the Quotient, as our fraction is proper, it will do that from the start.

So, given that 15 is smaller than 16 we will introduce a zero to its right to make it into 150. Now, letâ€™s solve it:

Â **150 $\div$ 16 $\approx$ 9**

Where:

**16 x 9 = 144Â **

Hence, a **Remainder** of 150 â€“ 144 = 6 is generated. Now, we shall repeat the process and add another **Zero** to the dividend which is now 6 and it becomes 60. Solving for it result in:

**60 $\div$ 16 $\approx$ 3**

Where:

**16 x 3 = 48Â **

Which produces a Remainder of 12, now solving for this would lead to:

**Â 120 $\div$ 16 $\approx$ 7**

Where:

**16 x 3 = 112Â **

Thus, we have a **Remainder** equal to 8. As we have gone through three iterations and produced a result up to **Third Decimal Place**, we can usually quit the process here. But if we look closely then we see that 8 would become 80, which is a **Multiple** of 16 so we can find the complete solution to this fraction.

**80 $\div$ 16 $\approx$ 5**

Where:

**16 x 5 = 80**

Thus, a viable **Quotient** is calculated, which is equal to 0.9375, with no **Remainder**.

*Images/mathematical drawings are created with GeoGebra.*