# What Is 8/11 as a Decimal + Solution With Free Steps

**The fraction 8/11 as a decimal is equal to 0.727.**

There are many different types of numbers, and **Decimal Numbers** are one of them. They are special as they are created by **Fractions**. A decimal number is composed of two parts, one is the **Whole Number** part, and the other is the **Decimal** part.

We know that a **Fraction**Â in the literal sense is defined as a smaller part of a bigger object. Similarly, in **Mathematics,** fractions represent a number broken down into smaller pieces.

So when a number i.e., the **Numerator** is divided by a denominator, the numerator is broken into a **Denominator** number of pieces, and one of them is represented by the said fraction. Finally, we talk about the method we use for finding the **Solution** to a division, this method is called **Long Division**. So letâ€™s go through the solution of our fraction.

## Solution

We begin by taking out the dividend and the divisor from our fraction. As we are aware that the numerator of a fraction is equivalent to the **Dividend** and the denominator is equivalent to the **Divisor**, we get the following:

**Dividend = 8**

**Divisor = 11**

Now, as we discussed earlier the division within a **Fraction** can be expressed in a very detailed fashion. For our fraction 8/11, we are dividing the number 8 into 11 pieces and then we grab **One** of those pieces and that is the value we are chasing. And it can be referred to as the **Quotient** given as:

**Quotient = Dividend $\div$ Divisor = 8 $\div$ 11**

Letâ€™s go through the **Long Division Solution** of this division:

Figure 1

## 8/11 Long Division Method

When solving a fractionâ€™s division using the **Long Division Method**, we have to keep two things in mind. One, we multiply the dividend by ten if it is smaller than the divisor and introduce the **Decimal** in the Quotient. And second, we find the **Closest Multiple** of the divisor to the dividend and subtract it from the dividend.

This subtraction leads to the generation of a **Remainder**, and it then becomes the new dividend. Now, as we know our dividend 8 is smaller than 11, letâ€™s introduce the **Decimal** and make it 80. Solving for it results in:

**80 $\div$ 11 $\approx$ 7**

Where:

**11 x 7 = 77**

So a **Remainder** of 80 â€“ 77 = 3 is produced, and solving further would give us the new dividend as 30, hence we have:

**30 $\div$ 11 $\approx$ 2**

Where:

**Â 11 x 2 = 22**

In this iteration, a **Remainder** equal to 30 â€“ 22 = 8 is produced, and we can see that this has produced our initial dividend again for us. We can solve once more for accuracy:

**80 $\div$ 11 $\approx$ 7**

Where:

**11 x 7 = 77**

Therefore, we have a **Repeating** set of remainders, 3 and 8, and thus we have a repeating decimal number as the **Quotient** which is **0.727**.

*Images/mathematical drawings are created with GeoGebra.*