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# Ray|Definition & Meaning

## Definition

A ray (in geometry) is a line characterized by a defined starting point (the terminus) with infinite length in only one particular direction (no ending point).Â

More precisely, given two points A_{1} and A_{2} in space, joining them with a half-infinite line $\mathsf{\overrightarrow{A_1A_2}}$ in the direction A_{1} to A_{2} results in a ray if and only if it passes through the entire set of ordered collinear points both beyond A_{2} {B_{1}, B_{2}, â€¦ B_{n}} and between A_{1} and A_{2} {C_{1}, C_{2}, â€¦ C_{n}} in that direction. Thus, the order of points along the ray would be (A_{1}, C_{1}, C_{2}, â€¦, C_{n}, A_{2}, B_{1}, B_{2}, â€¦, B_{n}), and we can say that it passes through all the points in space that lie in a particular direction from a defined starting point. We illustrate this in the following figure:

Figure 1 – A detailed illustration of a ray according to its definition.

## Visualization on Graphs

Since we cannot draw an infinite line, we draw rays as a **thin, finite line** originating at the** terminus** with an **arrow on the other end** to indicate infinite length. This symbolization might sound familiar because we draw** vectors** the same way.

While a ray has an **infinite length** and **direction**, a vector is a well-defined quantity with a **finite length **(magnitude) and **direction**. Therefore, much like a line segment, a vector has both a starting and an endpoint â€“ very different from a ray!

Figure 2 – The difference between the compact notation of a ray and a vector.

## Intuition and Relationship With Lines and Line Segments

A **line segment** has a **finite length** with **two endpoints**, say A and B, so it passes through all the points between A and B. On the other hand, a **line** is **infinite** on both ends (has no endpoints) and passes through all the points (x, y) in space that satisfy the equation of a line:

**y = mx + c **

Where m is the slope and c is the y-intercept of the line. In other words, if you **extend a line segment infinitely beyond its endpoints**, you get a line.

Now, you can think of a ray as a line, but instead of extending infinitely in two directions, it does so in only one. Equivalently, you can think of it as a line segment with only one endpoint and the length extending to infinity in the direction of the segmentâ€™s other endpoint. Thus, if the **terminus of a ray is (p, q)**, then the equation of the line represents the ray:

(y – q) = m(x – p), where x $\geq$ p and y $\geq$ q

And we can find the** direction** of the ray as an angle:

$\theta$ = arctan(m)

A geometrical ray has **only one point**: the terminus. We use either **angles** or **another** **point in space** to specify the **direction**.

## Point-finding on Rays

There are two steps to the process. The first step is to check whether the candidate pointâ€™s coordinates **(x _{c}, y_{c})** satisfy the rayâ€™s slope-terminus relationship. Assuming the rayâ€™s terminus is

**(p, q)**and the slope is

**m**, we have the following four cases:

- If m > 0 and ray points towards ($+\infty$, $+\infty$), the point must satisfy:
**x**._{c}$\geq$ p, y_{c}$\geq$ q - If m > 0 and ray points towards ($-\infty$, $-\infty$), the point must satisfy:
**x**._{c}$\leq$ p, y_{c}$\leq$ q - If m < 0 and ray points towards ($+\infty$, $-\infty$), the point must satisfy:
**x**._{c}$\geq$ p, y_{c}$\leq$ q - If m < 0 and ray points towards ($-\infty$, $+\infty$), the point must satisfy:
**x**._{c}$\leq$ p, y_{c}$\geq$ q

If the point (x_{c}, y_{c}) **passes the first check**, we must perform the second check. That is, does the point (x_{c}, y_{c}) satisfy:

**(y _{c} – q) / (x_{c} – p) = m**

Here, m is the known value of the slope. If the above **equality holds**, the point has passed both checks, and we can say that the **point (x _{c}, y_{c}) lies on the ray**.

Figure 3 – The first step in finding points on rays is to relate the ray direction to a quadrant.

A ray centered at the origin towards the first quadrant points to ($+\infty$, $+\infty$), while one towards the third points to ($-\infty$, $-\infty$). Note that this is **not always true** **for** **rays not centered at the origin**. In that case, the way to go is to check for one of the combinations of ($\pm\infty$, $\pm\infty$).

## A Solved Numerical Problem on Rays

### Example 1

Given the equation of a line y = 3x + 2, find a ray parallel to it with a terminus (3, 1) pointing towards ($+\infty$, $+\infty$).

### Solution

**Method 1: **To find a ray parallel to the line, we simply need the **angle** $\boldsymbol\theta$ of the line.

$\boldsymbol\theta$ **= arctan(3) = 71.565**${}^{\boldsymbol{\circ}}$

Now, place a **protractor** on the terminus **(3, 1)** and **draw a line** in that direction, and you are done!

The second method involves finding another point on the ray and joining the terminus with it. We can proceed in one of two ways. Remember that the slope is **increasing towards the northeast**, so all choices of **x** and **y** should be greater than the terminusâ€™ coordinates to pass the first check from earlier.

Let subscript ‘l’ represents the points on the line, and subscript ‘r’ represents the points on the ray.

**Method 2.1:** Use the equation of slope:

**m = (y _{r2} – y_{r1}) / (x_{r2} – x_{r1})**

Substitute m = 3, x_{r1} = 3, y_{r1} = 1, and one of x_{r2} $\geq$ 3 = 4 or y_{r2} $\geq$ 1 = 2. Suppose we set **x _{r2} = 4**. Then we need to

**solve for y**:

_{r2} y_{r2} = m(x_{r2} – x_{r1}) + y_{r1}

y_{r2} = 3(4 – 3) + 1 = 3 + 1 = 4

**y _{r2} = 4**

Therefore, we get the second point on the ray as:

**(x _{r2}, y_{r2}) = (4, 4)**

**Method 2.2:** Since the **ray is parallel to the line**, their points have a **specific offset**. To find it, we need to plug x_{l1} = 3 or y_{l1} = 1 into the equation of the **line** and find the **difference **between the resulting coordinates and (3, 1). Assuming we plug in x_{l1} = 3, then y_{l1}:

y_{l1} = 3(3) + 2 = 11

**(x _{l1}, y_{l1}) = (3, 11)**

offset = (x_{l1}, y_{l1}) – (x_{r1}, y_{r1})

**offset = (3, 11) – (3, 1) = (0, 10)**

Evidently, for the same x-coordinate, the y-coordinate is **offset by 10**. It follows that **all other points** on the ray and the line (for the same x) are shifted by 10 in the y-direction!

For another point on the line that also lies on the ray, choose x_{l2} $\geq$ 3 or y_{l2} $\geq$ 1. Say we pick x_{l2} = 4, then:

y_{l2} = 3(4) + 2 = 14

**(x _{l2}, y_{l2}) = (4, 14)**

Therefore, the coordinates of the point on the ray are:

(x_{r2}, y_{r2}) = (x_{l2} – 0, y_{l2} – 10) = (4 – 0, 14 – 10) = (4, 4)

**(x _{r2}, y_{r2}) = (4, 4)**

We get the same answer from both methods. **Joining the terminus** **to this point gives us the ray**! We draw this below:

Figure 4 – The ray AB (in red) from the equation of the line CD (in blue). Notice that the x and y intercept do not exist for the ray.

*All graphs/mathematical figures were created with GeoGebra.*